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50x^2-287.755x+361.015=2x
We move all terms to the left:
50x^2-287.755x+361.015-(2x)=0
We add all the numbers together, and all the variables
50x^2-289.755x+361.015=0
a = 50; b = -289.755; c = +361.015;
Δ = b2-4ac
Δ = -289.7552-4·50·361.015
Δ = 11754.960025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-289.755)-\sqrt{11754.960025}}{2*50}=\frac{289.755-\sqrt{11754.960025}}{100} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-289.755)+\sqrt{11754.960025}}{2*50}=\frac{289.755+\sqrt{11754.960025}}{100} $
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